(1)设甲种货车每辆运货物x吨,乙种货车每辆运货物y吨,则这批货物共有(3x+5y)吨,应付运费为30(3x+5y)元;根据题意,可得方程组:
2x+3y=15.5
5x+6y=35
解方程组,得:x=4,y=2.5
30(3x+5y)=30×(3×4+5×2.5)=735
答:货车应付运费735元.
(2)无解
(1)设甲种货车每辆运货物x吨,乙种货车每辆运货物y吨,则这批货物共有(3x+5y)吨,应付运费为30(3x+5y)元;根据题意,可得方程组:
2x+3y=15.5
5x+6y=35
解方程组,得:x=4,y=2.5
30(3x+5y)=30×(3×4+5×2.5)=735
答:货车应付运费735元.
(2)无解