Question

初二数学。分式子的基本性质

Answer 1

2(1)(10x+2×10y)/10x

=[10(x+2y)]/10x

=(x+2y)/x 不变

(2)[2(10x+10y)]/10x×10y

=[2×10(x+y)]/100xy

=[2(x+y)]/10xy

=(1/10)[2(x+y)/xy] ，缩小1/10

2(1)x≠-2

(2)x≠0