因式分解 (4x+3y)²-(2x+y)²

1个回答

  • (4x+3y)²-(2x+y)²

    = (4x+3y+2x+y)(4x+3y-2x-y)

    = (6x+4y)(2x+2y)

    =4(3x+2y)(x+y)

    (a+b+c)²-(a+b-c)²

    =(a+b+c+a+b-c)(a+b+c-a-b+c)

    =(2a+2b)(2c)

    =4c(a+b)

    4(2p+3q)²-(3p-q)²

    =[2(2p+3q)+(3p-q)][2(2p+3q)-(3p-q)]

    =(7p+5q)(p+7q)

    (x²+y²)²-x²y² 有平方吧

    =(x²+y²+xy)(x²+y²-xy)