∠DAB=∠ABC+∠ACB=180-124=56°
△ABD中,BD⊥AC,BD⊥AC,∠DAB+∠ABD=90°
BA平分∠DBC所以∠ABC=∠ABD
∠DAB=56°
∠ABD+∠DAB=90°
∠ABC=∠ABD
解得∠ABD=34° ∠ABC=34°
所以∠ACB=56°-34°=22°
不明白再问我
∠DAB=∠ABC+∠ACB=180-124=56°
△ABD中,BD⊥AC,BD⊥AC,∠DAB+∠ABD=90°
BA平分∠DBC所以∠ABC=∠ABD
∠DAB=56°
∠ABD+∠DAB=90°
∠ABC=∠ABD
解得∠ABD=34° ∠ABC=34°
所以∠ACB=56°-34°=22°
不明白再问我