Question

怎样求lim（x趋向1）时(x)的三次方-1 / (x)的平方-1的极限

Answer 1

原式=(x-1)(x²+x+1)/(x+1)(x-1)

=(x²+x+1)/(x+1)

所以极限=(1+1+1)/1+1)=3/2