cos^2X-sin^2X=1/2=cos2X
2X=2kπ±π/3
X=kπ±π/6
k=-2,X1=-2π+π/6=-11π/6
k=-1,X2=-π-π/6=-7π/6
X3=-π+π/6=-5π/6
k=0 ,X4=π/6
X5=-π/6
k=1,X6=π-π/6=5π/6
X7=π+π/6=7π/6
k=2,X8=2π-π=11π/6
求方程cos^2x-sin^2=1/2在区间[-2π,2π]上所有的解的和
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