角BAO=30,则有tan30=b/a=根号3/3,即有b^2=a^2/3
S(ABF)=1/2(c-a)*b=1/2(6-3根号3),即有bc-ab=6-3根号3
c^2=a^2+b^2=4a^2/3
c=2a/根号3
即有:2a/根号3*a/根号3-a*a/根号3=6-3根号3
a^2*(2/3-1/根号3)=6-3根号3
a^2=(18根号3-27)/(2根号3-3)=9
b^2=3
故方程是x^2/9-y^2/3=1
角BAO=30,则有tan30=b/a=根号3/3,即有b^2=a^2/3
S(ABF)=1/2(c-a)*b=1/2(6-3根号3),即有bc-ab=6-3根号3
c^2=a^2+b^2=4a^2/3
c=2a/根号3
即有:2a/根号3*a/根号3-a*a/根号3=6-3根号3
a^2*(2/3-1/根号3)=6-3根号3
a^2=(18根号3-27)/(2根号3-3)=9
b^2=3
故方程是x^2/9-y^2/3=1