Question

解不等式（x²+4x-5）(x²-2x+2)＞0

Answer 1

(x^2+4x-5)(x^2-2x+2)＞0

因为：x^2-2x+2=(x-1)^2+1>0

所以,原不等式等同于：x^2+4x-5>0

即：（x+5)(x-1)>0

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