Question

已知抛物线y=a(x-h)的平方的顶点为(-4,0)且经过点(2,1)求代数式4a+2h

Answer 1

h=4,则y=a(x-4)^2

1=a(2-4)^2,4a=1,a=1/4

4a十2h=4×1/4十2×4=9