Question

若x+17=y+7=z+6,求(x-y)^2+(y-z)^2+(z-x)^2的值

Answer 1

∵X+17=Y+7

∴X-Y=-10

∵Y+7=Z+6

∴Y-Z=-1

∵X+17=Z+6

∴Z-X=11

∴(x-y)^2+(y-z)^2+(z-x)^2=(-10)^2+(-1)^2+11^2=222