设一半路程是s,总路程是2s,前一半路程s所用时间t1,则:
1/2at1²=s (1)
整段路程2s所用时间t,则:
1/2at²=2s (2)
(1)与(2)式相除得:
(t1/t)²=1/2
t1/t=1/√2
后一半路程所用时间t2=t-t1,得:
t1/t2=t1/(t-t1)=1/(根号2-1)=1:(根号2-1)=根号2:1
选B
设一半路程是s,总路程是2s,前一半路程s所用时间t1,则:
1/2at1²=s (1)
整段路程2s所用时间t,则:
1/2at²=2s (2)
(1)与(2)式相除得:
(t1/t)²=1/2
t1/t=1/√2
后一半路程所用时间t2=t-t1,得:
t1/t2=t1/(t-t1)=1/(根号2-1)=1:(根号2-1)=根号2:1
选B