Question

若|x+2y-1|+y²+4y+4=0,求（2x-y）²-2（2x-y)(x+2y)+(x+2y)&

Answer 1

∵|x+2y-1|+y²+4y+4=0

∴|x+2y-1|+(y+2)²=0

∴x=5,y=-2

(2x-y)²-2(2x-y)(x+2y)+(x+2y)²

=[(2x-y)-(x+2y)]²

=(x-3y)²

=[5-3×(-2)]²

=11²

=121