Question

用do while 循环语句求自然对数e的近似值,要求其误差小于0.00001,

Answer 1

#include#include

double N_I(double n)

{

double ret= 1;

while(n)

{

ret*= n;

n--;

}

return ret;

}

void main()

{

double e= 2;

double n= 1, re;

do

{

n++;

re= 1/(N_I(n));

e+= re;

} while(re > 0.00001);

printf("%.10fn", e);}