|x+4|+(y+2/1)的平方=0
x+4=0
y+1/2=0
∴x=-4
y=-1/2
5x的平方y-{2xy的平方-2(xy-2/5x的平方)+xy}+5xy的平方
=5x²y-2xy²+2xy-5x²-xy+5xy²
=5x²y+3xy²+xy-5x²
=-40-3+2-80
=-121
|x+4|+(y+2/1)的平方=0
x+4=0
y+1/2=0
∴x=-4
y=-1/2
5x的平方y-{2xy的平方-2(xy-2/5x的平方)+xy}+5xy的平方
=5x²y-2xy²+2xy-5x²-xy+5xy²
=5x²y+3xy²+xy-5x²
=-40-3+2-80
=-121