原式=(9x²+6xy+y²-9x²-6xy+9y²-x²+9y²)÷2xy
=(19y²-x²)/2xy
[(3x+y)虏-3(3x-y)(x+y)-(x-3y)(x+3y)]÷(2xy)
1个回答
相关问题
-
急![(3x+y)²-3(3x-y)(x+y)-(x-3y)(x+3y)]÷(2xy)
-
x*（9x^3y-3xy^2）÷（-3x^2y）= 【（x+y）^2-（x-y）^2】÷（-4xy）=
-
姹倄虏+2xy-3y虏+3x+y+2
-
[x(x^2 y^2-xy)-y(x^2-x^3y)]÷3x^2y
-
已知x÷y=3,则x²+2xy－3y²÷(x²－xy+y²)=?
-
（9x3y4-6x4y3+3x2y3）÷______=-3x2y2+2x3y-xy．
-
[x(x²y²-xy)-2y(x²-x³y)÷3x²y
-
1.【x(x^2y^2-xy)-y(x^2-x^3y)]÷3x^2y
-
计算：[x（x2y2-xy）-y（x2-x3y）]÷3x2y．
-
计算(1)x×(9x^3y-3xy^2)÷（-3x^2y)(2)((x+y)^2-(x-y)^2)÷(-4xy)（3）三