连接BD
∵AB∥CD
∴∠ABD+∠BDE=180°
∵CD⊥BC
∴∠C=90°
∴∠CBD+∠CDB=90°
∴∠ABD+∠BDE+∠CBD+∠CDB
=∠ABC+∠CDE
=180°+90°
=270°
∵∠ABC=150°
∴∠CDE=120°
连接BD
∵AB∥CD
∴∠ABD+∠BDE=180°
∵CD⊥BC
∴∠C=90°
∴∠CBD+∠CDB=90°
∴∠ABD+∠BDE+∠CBD+∠CDB
=∠ABC+∠CDE
=180°+90°
=270°
∵∠ABC=150°
∴∠CDE=120°