Question

已知：y=e的x次方除以x的5次方,求dy

Answer 1

y=e^x/x^5=y=e^x*x^(-5)

y'=e^x*x^(-5)-5e^x*x^(-6)

=e^x(x-5)/x^6

dy=[e^x(x-5)/x^6]dx