Question

如图,直线AB,CD相交于O,OE平分角AOD,角AOC=60度,求角BOE.

Answer 1

∵AB和CD交于O

∠AOC=60°

∴∠AOD=180°-∠AOC=180°-60°=120°

∵OE平分∠AOD

∴∠AOE=1/2∠AOD=1/2×120°=60°

∴∠BOE=180°-∠AOE=180°-60°=120°