原式=log2[√(7/48)]+log2(12)-log2(√42)
=log2[√(7/48)×12÷√42]
=log2[√(144/6×48)]
=log2[√(1/2)]
=log2[2^(-1/2)]
=-1/2
1/2log2(7/48)+log2 12-1/2log2 42
4个回答
相关问题
-
log2 SQR(7/48)+log2 12 -1/2log2 42
-
log2(根号下7/48)+log2(12)-1/2log2(42)-1=?
-
log2 SQR(7/48)+log2 12 -1/2log2 48
-
化简下列各式 2、log2根号7/48+log小2 12-1/2log小2 42-1
-
求化简log2根号下48分之7+log2 12-log2 42
-
log2 √7/24+log2 12-log442
-
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
-
log2 3=a,log3 7=b,log42 56=?
-
1.计算1/2log3 12-log3 2=()
-
2log3(1/2)+log3(12)-(0.7)^0+0.25^-1 0