如果题目的意思是
(x+y)(x-y)+(x-y)²-(6x²y-2xy²)/2y
原式=x²-y²+x²-2xy+y²-2y(3x²-xy)/2y
=2x²-2xy-3x²+xy
=-x²-xy
=-x(x+y)
(X+Y)(X-Y)+(X-Y)^2-(6X^2y-2XY^2)除以2Y
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