[3(a-b)^3-2(b-a)^2-(a-b)]除以(a-b)
=[3(a-b)³-2(a-b)²-(a-b)]÷(a-b)
=3(a-b)²-2(a-b)-1
=[3(a-b)+1](a-b-1)
=(3a-3b+1)(a-b-1)
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[3(a-b)^3-2(b-a)^2-(a-b)]除以(a-b)
=[3(a-b)³-2(a-b)²-(a-b)]÷(a-b)
=3(a-b)²-2(a-b)-1
=[3(a-b)+1](a-b-1)
=(3a-3b+1)(a-b-1)
很高兴为您解答,【the1900】团队为您答题.
请点击下面的【选为满意回答】按钮,