Question

硝酸钾含量为99%,换算成氧化钾是多少? 硫酸钾含量为85%,换算成氧化钾是多少?

Answer 1

KNO3 1/2 K2O

101 1/2 * 94

99% x

101/(1/2*94) = 99%/x

x = 46.1 %

KNO3含量为99%,换算成氧化钾是 46.1 %

K2SO4 K2O

174 94

85% y

174/94 = 85% / y

y = 45.9 %

K2SO4含量为99%,换算成氧化钾是45.9 %