f(x)=sin(2x-π/6) 若不等式f(x)-m≥1对任意x∈[-π/12,π/2]皆成立,求实数m的取值范围
1个回答
x∈[0,5π/12]
π/3≤2x+π/3≤7π/6
-1/2≤sin(2x+π/3)≤1
-1≤2sin(2x+π/3)≤2
2sin(2x+π/3)2
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