(a+2)(a-2)(a²*²+4a²+16)
1个回答
(a+2)(a-2)(a^4+4a²+16)
=(a²-4)*(a²+4)²
=(a²-4)*(a²+4)*(a²+4)
=(a^4-16)*(a²+4)
=a^6+4a^4-16a²-64
相关问题
(4a+1)∧2-16a∧2(4a^2+1)^2-16a^2=(4a^2+4a+1)(4a^2-4a+1)怎么变成这样
16-a^2/a^2+8a+16÷a-4/2a+8×a-2/a+2
a1a2=4 a2=4 a1a2a3=9 a3=9/4 a1a2a3a4=16 a4=16/9 a1a2a3a4a5=2
(16-a^2)/(a^2+8a+16)/(a-4)/(2a+8)*(a-2)/(a+2)约分为最简分式
4a+2b-16-a-ab=0 4a+2b-16-a-ab=0
(a+2)(a-2)(a^+4a+16) 化简
√(16a^2-4a)/a=2√2怎么解?
((a-2)/(a+4))×((a²+8a+16)/4a²)
(1)、(a+2)(a-2)(a²+4)(a的4次方+16)=
a^4+4a^2+16因式分解