1X2+2X3+3X4+...+nX(n+1)= 1X2+2X3+3X4+...+10X11= (写过程,如1/3 乘.
1个回答
原式 = sum_{i=1}^{n}(i^2 + i)
= sum_{i=1}^{n}{i^2} + sum_{i=1}^{n}{i}
= n(n+1)(2n+1)/6 + n(n+1)/2
相关问题
1X2+2X3+3X4+...+10X11= 如1/3 乘.)
根号[(1x2x3+2x4x6+...+nx2nx3n)/(1x3x4+2x6x8+...+nx3nx4n))=?
1x2x3+2x3x4+.+nx(n+1)(n+2)=?
1x2+2x3+3x4+...+nx(n+1)=
1+2x2+3x2^2+4x2^3+.+nx2^n-1=?
1+2x2+3x2^2+4x2^3+.+nx2^n-1=?
求:S=1+2x+3x^2+4x^3+5x^4+…nx^(n-1)
2-(1-x)=-2 11x+2=5(2x+1) 3-x/2=x+4/3 1/4x=-1/2x+3 写好加10悬赏
Sn=1x2/2 + 2x3/2 +3x4/2+.+nx(n+1)/2 = __________
1)1x2+2x3+3x4+...+100x101= 2)1x2+2x3+3x4+...n(n+1)= (3)1x2x3