[(x-y)^7]÷(y-x)³-[4(x-y)²]²
3个回答
[(x-y)^7]÷(y-x)³-[4(x-y)²]²
=[(x-y)^7]÷[-(x-y)³-16(x-y)^4
=-(x-y)^4-16(x-y)^4
=-17(x-y)^4
相关问题
[(x+2y)(x-2y)-(x-4y)²]÷4y,其中x=-7,y=0.2
(x-y{)}{5}÷(y-x{)}{4}+(x+y)³÷(-x-y)² (-3){²}{
计算(x-y)^7÷(y-x)^6+9-x-y)^3÷(x+y)^2
解方程组 (1){7t-4s=7 (2){(x+y÷2)+(x-y÷3)=64t-2s=4 4(x+y)-5(x-y)=
[(x²+y²)-(x-y)²+2y(x-y)]÷4y=1,求4x/4x²-y&
计算【4(x+y)²-x-y】÷(x+y)
化简求值,4x^5y³÷[x^4y³÷[x³y÷(x³y²÷2xy²]},其中x=-1/2,y=3
1/x²×x³+x的7次方÷x² 2/、【(x-y)²+(x+y)(x-y)]÷
[(2x+y)²-y(y-4x)]÷[-1/4x]
4xy-4x²-y²/2x-y÷(4x²-y²)