证明sin^4a-cos^4a=sin^2a-cos^2a
1个回答
sin^4a - cos^4a
= (sin²a + cos²a)(sin²a - cos²a)
= 1×(sin²a - cos²a)
= sin²a - cos²a
相关问题
证明sin(4A)sin(2A)(1-cos(2A)) cos(4A)cos(2A)(1 cos(2A))=cos(2A
证明 sin^4a+cos^4a=1-2sin^2a乘以cos^2a
证明 sin^4a-cos^4a=1-2cos^2a
sin^4a-cos^4a=sin^2-cos^2a
sin^4a-cos^4a=sin^2a-cos^2a
sin^4a-cos^4a=sin^2a-cos^2a
证明(sin2a-sin2b)^2+(cos2a+cos2b)^2=4*(cos(a+b))^2
sin4a-cos4a=sin2a-cos2a 求证
证明Cos^A-Sin^A=1-2Sin^A=2Cos^A-1=cos^a-sin^a
已知(cos^4a)/cos^2b+(sin^4a)/sin^2b=1求证(cos^4b)/cos^2a+(sin^4b