Question

急!初二数学因式分解题目非常谢谢:[(x+P)+(x+q)][(x+q)-(x+q)] 和 (x²＋y

Answer 1

[(x+p)+(x+q)][(x+p)-(x+q)]

=(x+p)^2-(x+q)^2

=x^2+2px+p^2-x^2-2qx-q^2

=2px+p^2-2qx-q^2

(x^2+y^2)(x^2-y^2)

=(x^2)^2-(y^2)^2

=x^4-y^4

(2x+y)^2-(x+2y)^2

=(2x+y-x-2y)(2x+y+x+2y)

=(x-y)(3x+3y)

=3（x-y)(x+y)