解方程:(1)x^2-7x-1=0

1个回答

  • 解方程:

    (1)x^2-7x-1=0

    (x-3.5)^2=13.25

    x-3.5=±√13.25

    x1=3.5+√13.25

    x2=3.5-√13.25 .

    (2)2x^2+3x=3

    x^2+1.5x-1.5=0

    Δ=1.5^2+4*1.5=8.25

    x1=(-1.5+√8.25)/2

    x2=(-1.5-√8.25)/2

    (3)x^2-2x+1=25

    (x-1)^2=25

    x-1=±5

    x1=6 x2=-4

    (4) x(2x-5)=4x-10

    2x^2-5x=4x-10

    2 x^2-9x+10=0

    (2x-5)(x-2)=0

    x1=5/2 x2=2

    (5) x^2+5x+7=3x+11

    x^2+2x-4=0

    (x+1)^2=5

    x+1=±√5

    x1=√5-1

    x2=-√5-1 .

    (6)1-8x+16x^2=2-8x

    16x^2=1

    x^2=1/16

    x=±1/4

    x1=1/4 x2=-1/4