(-6x^2y^3+2x^2y-1/2xy)÷(-1/2xy)
=(-6x^2y^3+2x^2y-1/2xy)*(-2xy)
=12x^3y^4-4x^3y^2+x^2y^2
(-6x^2y^3+2x^2y-1/2xy)÷(-1/2xy)
1个回答
相关问题
-
计算(3x^3y-x^2y+1/2xy)÷(-1/2xy）
-
求值（x^2+xy)/(x^2-2xy-3y^2)*(3y-x)/(x-y)+(x^-1+y^-1)÷(x^-1-y^-
-
求值（x^2+xy)/(x^2-2xy-3y^2)*(3y-x)/(x-y)+(x^-1+y^-1)÷(x^-1-y^-
-
求助：x²+y²/ x²+2xy+y²+2/xy÷（1/x+1/y）²
-
计算（1）(−2xy2)2÷(−14x2y2)•4xy（2）（3x-2y+1）（3x+2y-1）
-
①-1/3（9x^2-3)+6(2/3x^2+1)②x^2y-(6xy+3x^2y-xy^2)+（5xy+2x^2y)过
-
(x+y)(x-y)+(x-y)^2-(6x^2×y÷2y-2xy^2÷2y)其中x=-3,y=1/3
-
(3x^3y^2)^4÷(6x^2y)^2-(-1/3x^3y^2)^2·(1/2xy)^2
-
[(-3xy)²·x³-2x² ·（3xy²）³ ·1/2y]÷9x&
-
计算(1)x×(9x^3y-3xy^2)÷（-3x^2y)(2)((x+y)^2-(x-y)^2)÷(-4xy)（3）三