2log3^2-log3^(32/9)+log3^8
1个回答
2log3^2-log3^(32/9)+log3^8
=log3^2^2-log3^(32/9)+log3^8
=log3^[2^2*8/(32/9)]
=log3^9
=log3^(3^2)
=2
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