Question

如图,直线AB与CD相交于点O,OE⊥CD,OF⊥AB,角DOF=55°,求角BOE和角AOC的度数

Answer 1

∠BOE=55º,∠AOC=35º (如果OA,OF在CD一侧,OB,OE在CD另一侧：∠DOF+∠FOA+∠AOC=180º∵OF⊥AB∴∠FOA=90º 故∠AOC=35º同理,∠AOC+∠COE+∠EOB+=180º∵OE⊥CD∴∠COE=90º 故∠BOE=...