(1)∠OBC+∠OCB=1/2(∠ACB+∠ABC)=1/2(180-∠A)=90-1/2∠A
所以∠BOC=180-(90-1/2∠A)=90+1/2∠A
(2)∠ABO+∠ACO=1/2(180-∠B)+1/2(180-∠C)=180-1/2∠B-1/2∠C
=180-1/2(180-∠A)=90+1/2∠A
所以∠BOC=90-1/2∠A
第三个看不懂
(1)∠OBC+∠OCB=1/2(∠ACB+∠ABC)=1/2(180-∠A)=90-1/2∠A
所以∠BOC=180-(90-1/2∠A)=90+1/2∠A
(2)∠ABO+∠ACO=1/2(180-∠B)+1/2(180-∠C)=180-1/2∠B-1/2∠C
=180-1/2(180-∠A)=90+1/2∠A
所以∠BOC=90-1/2∠A
第三个看不懂