1、设方程的两个根分别是X1,X2且令X1=1.
X1+X2=﹣﹙﹣19/3﹚=19/3
X1X2=m/3
所以解得 m=16
X2=16/3
2、X2+X1=-﹙4/2﹚=﹣2
X2X1=﹣3/2
(1)﹙X1+1﹚﹙X2+1﹚=X1X2+X1+X2+1=﹙﹣3/2﹚+﹙﹣4/2﹚+1=﹣5/2
(2) X2/X1+X1/X2=[﹙X2﹚²+﹙X1﹚²]/X2X1=[﹙X2+X1﹚²-2X2X1]/X2X1=[﹙﹣2﹚²-2﹙﹣3/2﹚]/﹙﹣3/2﹚=﹣14/3
1、设方程的两个根分别是X1,X2且令X1=1.
X1+X2=﹣﹙﹣19/3﹚=19/3
X1X2=m/3
所以解得 m=16
X2=16/3
2、X2+X1=-﹙4/2﹚=﹣2
X2X1=﹣3/2
(1)﹙X1+1﹚﹙X2+1﹚=X1X2+X1+X2+1=﹙﹣3/2﹚+﹙﹣4/2﹚+1=﹣5/2
(2) X2/X1+X1/X2=[﹙X2﹚²+﹙X1﹚²]/X2X1=[﹙X2+X1﹚²-2X2X1]/X2X1=[﹙﹣2﹚²-2﹙﹣3/2﹚]/﹙﹣3/2﹚=﹣14/3