Question

简便计算(3m^2n^2)^2X(-2m^2)^4X(-n^2)^5 2008^2-2007X2009 (a+b)(a^

Answer 1

(3m^2n^2)^2X(-2m^2)^4X(-n^2)^5

=[(3m^2n^2)(4m^4)(n^4)}^2X(-n)

=-n(12m^6n^6)*2

=-144m^12n^13

2008^2-2007X2009

=2008^2-(2008-1)(2008+1)

=2008^2-2008^2+1

=1

(a+b)(a^2+b^2)(a-b)

=(a^2-b^2)(a^2+b^2)

=a^4-b^4

(3x^2y-xy^2+1/2xy)除以（-1/2xy)

=[3xy(x-y)+1/2xy]*(-2xy)

=-6x^2y^2(x-y)-1