Question

在△ABC中,a,b,c是三角形的三边,化简根号(a-b+c)的平方—|c-a-b|

Answer 1

∵a,b,c是△ABC的三边

∴a+b＞c,a-b＜c

∴原式=根号下[(a-b)+c]²—|c-a-b|

=|(a-b)+c|—|c-(a+b)|

=-[(a-b)+c]-｛-[c-(a+b)｝

=2b-2c