求下列函数的反函数:
①、y=2sin3x;定义域:-π/6≤x≤π/6;值域:-2≤y≤2;
sin3x=y/2,3x=arcsin(y/2),x=(1/3)arcsin(y/2);
交换x,y,即得反函数y=(1/3)arcsin(x/2);定义域:-2≤x≤2;值域:-π/6≤y≤π/6;
②、y=1+㏑(x+2);定义域:x>-2;值域:-∞
求下列函数的反函数:
①、y=2sin3x;定义域:-π/6≤x≤π/6;值域:-2≤y≤2;
sin3x=y/2,3x=arcsin(y/2),x=(1/3)arcsin(y/2);
交换x,y,即得反函数y=(1/3)arcsin(x/2);定义域:-2≤x≤2;值域:-π/6≤y≤π/6;
②、y=1+㏑(x+2);定义域:x>-2;值域:-∞