Question

因式分解3题、6y^4+19^2+10,6（a+b)^2+a+b-35,7(x-1)^2+4(x-1)(y+2)-20(

Answer 1

6y^4+19^2+10,

=(3y^2+2)(2y^2+5)

6（a+b)^2+a+b-35,

=[3(a+b)-7][2(a+b)+5]

=(3a+3b-7)(2a+2b+5)

7(x-1)^2+4(x-1)(y+2)-20(y+2)^2

=[7(x-1)-10(y+2)][(x-1)+2(y+2)]

=(7x-7-10y-20)(x-1+2y+4)

=(7x-10y-27)(x+2y+3)