(1) I=
U
R =
8V
R , I′=
U′
R =
10V
R
∵I′-I=0.2A
即:
10V
R -
8V
R =0.2A ,
∴R=10Ω
(2) P=
U 2
R =
(8V) 2
10Ω =6.4W , P′=
U′ 2
R =
(10V) 2
10Ω =10W
∴P′-P=10W-6.4W=3.6W
故答案为:10,36.
(1) I=
U
R =
8V
R , I′=
U′
R =
10V
R
∵I′-I=0.2A
即:
10V
R -
8V
R =0.2A ,
∴R=10Ω
(2) P=
U 2
R =
(8V) 2
10Ω =6.4W , P′=
U′ 2
R =
(10V) 2
10Ω =10W
∴P′-P=10W-6.4W=3.6W
故答案为:10,36.