Question

y=(x+1)(x+2)(x+3) 它的导数用复合函数做

Answer 1

y=(x+1)(x+2)(x+3)

y'=(x+1)'(x+2)(x+3)+(x+1)(x+2)'(x+3)+(x+1)(x+2)(x+3)'

=(x+2)(x+3)+(x+1)(x+3)+(x+1)(x+2)

=(x²+5x+6)+(x²+4x+3)+(x²+3x+2)

=3x²+12x+11