已知函数f(x)=2√2cos(x+π/4)cos(x-π/4)+2√2sinxcosx 化为单一体
1个回答
f(x)=2√2cos(x+π/4)cos(x-π/4)+2√2sinxcosx
=√2[cos2x+cos(π/2)]+√2sin2x
=√2(cos2x+sin2x)
=2sin(2x+π/4).
相关问题
已知函数f(x)=2√3sinxcosx-2cos(x+π/4)cos(x-π/4) ,
已知函数f(x)=cos(x+π/4)cos(x-π/4)+2tsinxcosx-sin(x+π/4)cos(x-π/4
已知函数f(x)=cos(2x- π 3 )+2sin(x- π 4 )cos(x- π 4 ),x∈R
已知函数 f(x)=2co s 2 (x- π 6 )+2sin(x- π 4 )cos(x- π 4 )-1 .
已知函数f(x)=cos^2(π/4+x)cos2(π/4-x)求f(π/12)的值
已知函数f(x)=cos^2(π/4+x)cos2(π/4-x)求f(π/12)的值
已知函数f(x)=cos2(x+π/12)+sinxcosx
已知函数f(x)=(4cos^4x-2cos2x-1)/[tan(π/4+x)sin^2(π/4-x)] 求f(-17π
已知函数f(x)=(4cos^4x-2cos2x-1)/[tan(π/4+x)sin^2(π/4-x)] 求f(-17π
已知函数f(x)已知函数f(x)=2√3sin(x/2+π/4)cos(x/2+π/4)-sin(x+π)