(1).P(X>10)=∫[10,+∞](1/5)e^(-x/5)dx
=e^(-2)
=0.1353.
(2).b(2,0.1353),即
P(Y=0)=(1-0.1353)^2=0.7477,
P(Y=1)=2*0.1353*(1-0.1353)=0.2340,
P(Y=2)=0.1353^2=0.0183.
Y(>=1)=1-P(Y=0)=0.2523.
(1).P(X>10)=∫[10,+∞](1/5)e^(-x/5)dx
=e^(-2)
=0.1353.
(2).b(2,0.1353),即
P(Y=0)=(1-0.1353)^2=0.7477,
P(Y=1)=2*0.1353*(1-0.1353)=0.2340,
P(Y=2)=0.1353^2=0.0183.
Y(>=1)=1-P(Y=0)=0.2523.