设x=a^(1/3)=0.1 y=b^(1/3)
∴原式=(x^4-8xy³)/(x²+2xy+4y²)÷(1-2y/x)
=x(x-2y)(x²+2xy+4y²)/(x²+2xy+4y²)*x/(x-2y)
=x²
=0.1²
=0.01
幂函数 基础计算题2
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设x=a^(1/3)=0.1 y=b^(1/3)
∴原式=(x^4-8xy³)/(x²+2xy+4y²)÷(1-2y/x)
=x(x-2y)(x²+2xy+4y²)/(x²+2xy+4y²)*x/(x-2y)
=x²
=0.1²
=0.01