1.假设甲,乙浓度分别为x,y.倒出盐水a克.则
[(120-a)x+ay]/120=[(80-a)y+ax]/80
2(120-a)x+2ay=3(80-a)y+3ax
240x-2ax+2ay=240y-3ay+3ax
5ax-5ay=240x-240y
5a(x-y)=240(x-y)
a=48.(x!=y)
2.设胜x场,则(不败成绩,所以败0场)平(7-x)场.
3x+(7-x)=17
x=5
1.假设甲,乙浓度分别为x,y.倒出盐水a克.则
[(120-a)x+ay]/120=[(80-a)y+ax]/80
2(120-a)x+2ay=3(80-a)y+3ax
240x-2ax+2ay=240y-3ay+3ax
5ax-5ay=240x-240y
5a(x-y)=240(x-y)
a=48.(x!=y)
2.设胜x场,则(不败成绩,所以败0场)平(7-x)场.
3x+(7-x)=17
x=5