Question

如果分式(x^2-5x+6)/2x^2-2x-4)的值为0,则x的值为( )

Answer 1

(x^2-5x+6)/2x^2-2x-4)

=(x-2)(x-3)/[2(x-2)(x+1)]

=(x-3)/[2(x+1)]=0

x-3=0

x=3