Question

概率统计题求详解某仪器有3个独立工作原件。他们损坏的概率是为0.1。当一个原件损坏时仪器发生故障的概率是0.25；当俩个

Answer 1

当一个原件损坏时：P1=0.1*0.9*0.9*0.25=0.02025当两个原件损坏时：P2=0.1*0.1*0.9*0.6=0.0054当三个原件损坏时：P3=0.1*0.1*0.1*0.95=0.00095所以P总=P1+P2+P3=0.0257