Question

怎么计算下面的矩阵0.2 0.3 0.4 0.10.1 0.8 0.1 0B1=( 0.1644,0.2848,0.44

Answer 1

记B1=（a,b,c,d）则

a=0.1644*0.2+0.2848*0.1+0.4457*0.5+0.1051*0.8=0.3683

b=0.1644*0.3+0.2848*0.8+0.4457*0.3+0.1051*0.2=0.4319

c=0.1644*0.4+0.2848*0.1+0.4457*0.2+0.1051*0 =0.1834

d=0.1644*0.1+0.2848*0 +0.4457*0 +0.1051*0 =0.0164

即B1=（0.3683,0.4319,0.1834,0.0164）