Question

如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB

Answer 1

∵AB⊥AC,AD⊥AE,

∴∠BAC=∠DAE=90°,

∴∠BAC+∠CAE=∠EAD+∠CAE,即∠BAE=∠CAD,

∵AB=AC,AD=AE

∴ΔDAC≌ΔEAB(SAS).