Question

已知f(x)=ax+bsin3x+1且f(5)=7求f(-5)

Answer 1

f(x)=ax+bsin3x+1

∵f(5)=5a+b*sin15+1=7

∴5a+b*sin15=6

∴f(-5)=-5a-b*sin15+1

=-(5a+bsin15)+1

=-6+1

=-5.