已知2x-y=10 求代数式[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y的值
3个回答
[(x∧2+y∧2)-(x-y)∧2+2y(x-y)]÷4y
=(2xy+2xy-2y^2)/(4y)
=(2x-y)/2
=10/2
=5
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